Active Directory example with referral enabled

This example covers the scenario where more than one Active Directory domains work together, and it’s needed the following parameter.

LDAP Structure

dc=com
    dc=company
        ou=OPENKM
            cn=ROLE_ADMIN
                member=okmAdmin
                member=user1
                member=user2
            cn=ROLE_USER
                member=user3
                member=user4
            cn=ROLE_XXXX
            cn=ROLE_YYYY
                ...
        ou=organization1
            sAMAccountName=okmAdmin
                memberOf=CN=ROLE_ADMIN,OU=OPENKM,DC=company,DC=com
                mail=okmAdmin@mail.com
                cn=OpenKM Administrator
            sAMAccountName=user1
                memberOf=CN=ROLE_ADMIN,OU=OPENKM,DC=company,DC=com
                mail=user1@mail.com
                cn=User Name 1
            sAMAccountName=user2
                memberOf=CN=ROLE_ADMIN,OU=OPENKM,DC=company,DC=com
                mail=user2@mail.com
                cn=User Name 3
        ou=organization2
            sAMAccountName=user3
                memberOf=CN=ROLE_USER,OU=OPENKM,DC=company,DC=com
                mail=user3@mail.com
                cn=User Name 3
            sAMAccountName=user4
                memberOf=CN=ROLE_USER,OU=OPENKM,DC=company,DC=com
                mail=user4@mail.com
                cn=User Name 4

Valid groups:

• cn=ROLE_ADMIN,ou=OPENKM,dc=company,dc=com
• cn=ROLE_USER,ou=OPENKM,dc=company,dc=com
• cn=ROLE_XXXX,ou=OPENKM,dc=company,dc=com
• cn=ROLE_YYYY,ou=OPENKM,dc=company,dc=com

Valid users:

• cn=user1,ou=organization1,dc=company,dc=com
• cn=user2,ou=organization1,dc=company,dc=com
• cn=user3,ou=organization2,dc=company,dc=com
• cn=user4,ou=organization2,dc=company,dc=com

Note

Any distinguished name includes by default dc=company,dc=com

Configuration parameters

Go to Administration > Configuration parameters:

Field / Property	Type	Description
principal.adapter	String	com.openkm.principal.LdapPrincipalAdapter
system.login.lowercase	String	true
principal.ldap.server	String	ldap://192.168.xxx.xxx:389
principal.ldap.security.principal	String	CN=Administrator,OU=OPENKM,DC=company,DC=com
principal.ldap.security.credentials	String	password
principal.ldap.referral	String	follow
principal.ldap.users.from.roles	Boolean	false
principal.ldap.user.attribute	String	sAMAccountName
principal.ldap.user.search.base	List	DC=company,DC=com
principal.ldap.user.search.filter	String	(objectclass=user)
principal.ldap.username.attribute	String	cn
principal.ldap.username.search.base	String	DC=company,DC=com
principal.ldap.username.search.filter	String	(&(objectClass=person)(sAMAccountName={0}))
principal.ldap.mail.attribute	String	mail
principal.ldap.mail.search.base	String	DC=company,DC=com
principal.ldap.mail.search.filter	String	(&(objectClass=person)(sAMAccountName={0}))
principal.ldap.role.attribute	String	cn
principal.ldap.role.search.base	List	DC=company,DC=com
principal.ldap.role.search.filter	String	(objectclass=group)
principal.ldap.roles.by.user.attribute	String	memberOf
principal.ldap.roles.by.user.search.base	String	DC=company,DC=com
principal.ldap.roles.by.user.search.filter	String	(&(objectClass=person)(sAMAccountName={0}))
principal.ldap.users.by.role.attribute	String	member
principal.ldap.users.by.role.search.base	String	DC=company,DC=com
principal.ldap.users.by.role.search.filter	String	(&(objectClass=group)(CN={0}))

OpenKM.xml

• Parameter follow indicates several domains servers working together ( balanced ).
• Users defined in any Active Directory node will be able to log in, because it has defined DC=company,DC=com as the base filter.
• Any user authenticated in Active Directory can log in because it has not any filtering clause.
• Groups read by OpenKM can be defined in an Active Directory node, because it has defined DC=company,DC=com as the base filter.

<security:authentication-manager alias="authenticationManager">
    <security:authentication-provider ref="ldapAuthProvider" />
  </security:authentication-manager>

  <beans:bean id="contextSource" class="org.springframework.security.ldap.DefaultSpringSecurityContextSource">
    <beans:constructor-arg value="ldap://192.168.xxx.xxx:389"/>
    <beans:property name="userDn" value="CN=Administrator,OU=OPENKM,DC=company,DC=com"/>
    <beans:property name="password" value="****"/>
    <beans:property name="baseEnvironmentProperties">
      <beans:map>
        <beans:entry>
          <beans:key>
            <beans:value>java.naming.referral</beans:value>
          </beans:key>
          <beans:value>follow</beans:value>
        </beans:entry>
      </beans:map>
    </beans:property>
  </beans:bean>

  <beans:bean id="ldapAuthProvider" class="org.springframework.security.ldap.authentication.LdapAuthenticationProvider">
    <beans:constructor-arg>
      <beans:bean class="org.springframework.security.ldap.authentication.BindAuthenticator">
        <beans:constructor-arg ref="contextSource"/>
        <beans:property name="userSearch" ref="userSearch"/>
      </beans:bean>
    </beans:constructor-arg>
    <beans:constructor-arg>
      <beans:bean class="org.springframework.security.ldap.userdetails.DefaultLdapAuthoritiesPopulator">
        <beans:constructor-arg ref="contextSource"/>
        <beans:constructor-arg value="DC=company,DC=com"/>
        <beans:property name="groupSearchFilter" value="member={0}"/>
        <beans:property name="groupRoleAttribute" value="cn"/>
        <beans:property name="searchSubtree" value="true" />
        <beans:property name="convertToUpperCase" value="false" />
        <beans:property name="rolePrefix" value="" />
      </beans:bean>
    </beans:constructor-arg>
  </beans:bean>

  <beans:bean id="userSearch" class="org.springframework.security.ldap.search.FilterBasedLdapUserSearch">
    <beans:constructor-arg index="0" value="DC=company,DC=com" />
    <beans:constructor-arg index="1" value="sAMAccountName={0}" />
    <beans:constructor-arg index="2" ref="contextSource" />
    <beans:property name="searchSubtree" value="true" />
  </beans:bean>